A light string passing over a smooth light&nb | vedclass

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Question

$\mathrm{a}=\left(\frac{\mathrm{m}_{2}-\mathrm{m}_{1}}{\mathrm{m}_{1}+\mathrm{m}_{2}}\right) \mathrm{g}$

$\frac{g}{8}=\left(\frac{m_{2}-m_{1}}{m_{1

Vedclass · Accepted Answer

$9 : 7$

Vedclass · Answer

$\mathrm{a}=\left(\frac{\mathrm{m}_{2}-\mathrm{m}_{1}}{\mathrm{m}_{1}+\mathrm{m}_{2}}\right) \mathrm{g}$

$\frac{g}{8}=\left(\frac{m_{2}-m_{1}}{m_{1}+m_{2}}\right) g$

$m_{1}+m_{2}=8 m_{2}-8 m_{1}$

$9 m_{1}=7 m_{2}$

$\frac{m_{2}}{m_{1}}=\frac{9}{7}$

A light string passing over a smooth light pulley connects two block of masses $m_1$ and $m_2$ (vertically). If the acceleration of the system is $\left( {\frac{g}{8}} \right)$, then the ratio of masses is

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